11.3 Some Reactions of the Halide Ions

Cambridge International AS Level Chemistry | 9701


2026 📋 Syllabus Objectives

By the end of these notes, you should be able to:

  1. Describe the relative reactivity of halide ions as reducing agents
  2. Describe and explain the reactions of halide ions with:
    • (a) Aqueous silver ions, followed by aqueous ammonia
    • (b) Concentrated sulfuric acid, including balanced chemical equations

Section 1 — Halide Ions as Reducing Agents

What is a reducing agent?

A reducing agent is a substance that gives away electrons to something else. When a halide ion gives away electrons, it loses them — and losing electrons is called oxidation. So when a halide ion acts as a reducing agent, the halide ion itself gets oxidised.

Think of it like this: a reducing agent is a generous electron donor. The more easily it donates electrons, the stronger a reducing agent it is.

The four halide ions are: F⁻ (fluoride), Cl⁻ (chloride), Br⁻ (bromide), and I⁻ (iodide).


The Trend in Reducing Power

The reducing power of the halide ions increases as you go down Group 17, in this order:

F⁻ < Cl⁻ < Br⁻ < I⁻

(weakest reducing agent → strongest reducing agent)

This means:

  • Fluoride (F⁻) is the weakest reducing agent
  • Iodide (I⁻) is the strongest reducing agent

Why Does This Trend Exist? — Ionic Radius

To understand why this happens, you need to think about the size of each halide ion.

Ionic radius means the size of an ion — how large it is. Going down Group 17, each halide ion has more electron shells (layers of electrons), so the ions get progressively larger:

Halide IonNumber of Electron ShellsRelative Size
F⁻2Smallest
Cl⁻3
Br⁻4
I⁻5Largest

Now here is the key question: why does a larger ion give away electrons more easily?

There are two reasons that work together:

Reason 1 — The outermost electrons are further from the nucleus. The nucleus (the centre of the atom) is positively charged. It attracts the negatively charged electrons and holds them in place. In a larger ion, the outermost electrons are much further away from the nucleus, so the pull of the nucleus on them is weaker.

Reason 2 — More shielding by inner electrons. In a larger ion, there are more inner electron shells sitting between the nucleus and the outermost electrons. These inner electrons "shield" (block) the outermost electrons from feeling the full attractive pull of the nucleus. This makes it even easier for the outermost electrons to escape.

The result: Because the outermost electrons in a larger ion are held less tightly, they can be donated (given away) more easily. This is why iodide (I⁻), being the largest halide ion, is the strongest reducing agent — it loses electrons most easily.

Sign in to view full notes