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By the end of this topic, you should be able to:
A potential divider is a circuit that splits (or divides) the voltage from a power source between two or more components. Think of it like sharing a pizza between friends—the total voltage gets divided up among the resistors in the circuit.
When two resistors are connected in series (one after the other), the voltage from the battery is shared between them. The bigger the resistance of a resistor, the bigger the share of voltage it gets.
Potential dividers have three main purposes:
You'll find potential dividers in everyday devices like volume controls on speakers and in sensor circuits that detect light or temperature changes.
Here's how the voltage divides between two resistors:
V_out = (R₂ / (R₁ + R₂)) × V_in
Where:
Important rule: The resistor that you're measuring V_out across always goes in the numerator (top) of the fraction.
In a series circuit, the current is the same through all components. Using Ohm's Law (V = IR):
The voltage across each resistor is proportional to its resistance. If you double the resistance, you double the voltage across it (assuming the other resistor stays the same).
A potential divider circuit has a 12 V battery connected to two resistors in series: 20 kΩ and 10 kΩ. Calculate the voltage across the 10 kΩ resistor.
Solution:
Step 1: Identify what we know
Step 2: Use the potential divider formula
V_out = (R₂ / (R₁ + R₂)) × V_in
V_out = (10 / (20 + 10)) × 12
V_out = (10 / 30) × 12
V_out = 4 V
The voltage across the 10 kΩ resistor is 4 V.
A potential divider has two resistors: 12 kΩ and 20 kΩ in series. The voltage across the 20 kΩ resistor is 5.3 V. Calculate the input voltage.
Solution:
Step 1: Identify what we know
Step 2: Rearrange the formula to find V_in
V_out = (R₂ / (R₁ + R₂)) × V_in
V_in = V_out × ((R₁ + R₂) / R₂)
V_in = 5.3 × ((12 + 20) / 20)
V_in = 5.3 × (32 / 20)
V_in = 5.3 × 1.6
V_in = 8.5 V
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