1.6 Vectors

2026 Syllabus Objectives

  1. Use the equation of a plane in any of the forms ax+by+cz=dax + by + cz = d or rn=p\mathbf{r} \cdot \mathbf{n} = p or r=a+λb+μc\mathbf{r} = \mathbf{a} + \lambda\mathbf{b} + \mu\mathbf{c} and convert equations of planes from one form to another as necessary in solving problems

  2. Recall that the vector product a×b\mathbf{a} \times \mathbf{b} of two vectors can be expressed either as absinθn^|\mathbf{a}||\mathbf{b}|\sin \theta \, \hat{\mathbf{n}}, where n^\hat{\mathbf{n}} is a unit vector, or in component form as (a2b3a3b2)i+(a3b1a1b3)j+(a1b2a2b1)k(a_2b_3 - a_3b_2)\mathbf{i} + (a_3b_1 - a_1b_3)\mathbf{j} + (a_1b_2 - a_2b_1)\mathbf{k}

  3. Use equations of lines and planes, together with scalar and vector products where appropriate, to solve problems concerning distances, angles and intersections, including:

    • Determining whether a line lies in a plane, is parallel to a plane or intersects a plane, and finding the point of intersection of a line and a plane when it exists
    • Finding the foot of the perpendicular from a point to a plane
    • Finding the angle between a line and a plane, and the angle between two planes
    • Finding an equation for the line of intersection of two planes
    • Calculating the shortest distance between two skew lines
    • Finding an equation for the common perpendicular to two skew lines

🔑 Key Concepts and Definitions

Scalar Product

The scalar product (or dot product) of two vectors a\mathbf{a} and b\mathbf{b} is defined as:

ab=abcosθ\mathbf{a} \cdot \mathbf{b} = |\mathbf{a}||\mathbf{b}|\cos \theta

where θ\theta is the angle between the two vectors.

Vector Product

The vector product (or cross product) of two vectors results in a vector that is perpendicular to the plane containing the two original vectors. It is a fundamental tool for finding normal vectors to planes and solving geometric problems.

Unit Vector

A unit vector is a vector with a magnitude of 1. It is often used to indicate direction without considering magnitude.

Common Perpendicular

A line that is perpendicular to two skew lines (non-parallel, non-intersecting lines) is called a common perpendicular.


📐 Equation of a Plane

A plane in three-dimensional space can be represented in several different forms. Understanding these forms and being able to convert between them is essential for solving problems involving planes.

Form 1: Cartesian Form

ax+by+cz=dax + by + cz = d

where aa, bb, cc, and dd are constants, and (a,b,c)(a, b, c) represents the normal vector to the plane.

Form 2: Vector Form (Scalar Product)

rn=p\mathbf{r} \cdot \mathbf{n} = p

where:

  • r=xi+yj+zk\mathbf{r} = x\mathbf{i} + y\mathbf{j} + z\mathbf{k} is the position vector of a general point on the plane
  • n\mathbf{n} is the normal vector to the plane
  • pp is a scalar constant

Form 3: Parametric Form

r=a+λb+μc\mathbf{r} = \mathbf{a} + \lambda\mathbf{b} + \mu\mathbf{c}

where:

  • a\mathbf{a} is the position vector of a known point on the plane
  • b\mathbf{b} and c\mathbf{c} are two non-parallel direction vectors lying in the plane
  • λ\lambda and μ\mu are scalar parameters

Converting Between Forms

Converting from Cartesian to Vector Form:

If the plane is given as ax+by+cz=dax + by + cz = d, then the normal vector is n=ai+bj+ck\mathbf{n} = a\mathbf{i} + b\mathbf{j} + c\mathbf{k}, and the vector form is r(ai+bj+ck)=d\mathbf{r} \cdot (a\mathbf{i} + b\mathbf{j} + c\mathbf{k}) = d.

Converting from Vector Form to Cartesian:

If rn=p\mathbf{r} \cdot \mathbf{n} = p where n=n1i+n2j+n3k\mathbf{n} = n_1\mathbf{i} + n_2\mathbf{j} + n_3\mathbf{k}, then substituting r=xi+yj+zk\mathbf{r} = x\mathbf{i} + y\mathbf{j} + z\mathbf{k} gives n1x+n2y+n3z=pn_1x + n_2y + n_3z = p.

Converting from Parametric to Cartesian:

Given r=a+λb+μc\mathbf{r} = \mathbf{a} + \lambda\mathbf{b} + \mu\mathbf{c}, find the normal vector n\mathbf{n} by computing the vector product b×c\mathbf{b} \times \mathbf{c}. Then use a known point on the plane to find the constant.

Sign in to view full notes