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By the end of this topic, you should be able to:
Integration is the opposite (or reverse) of differentiation. If differentiation tells us the rate of change of a function, integration does the opposite - it finds the original function when we know its rate of change.
Think of it this way:
For example:
The symbol for integration is ∫ (called an integral sign). When we write ∫ 2x dx, it means "integrate 2x with respect to x".
The dx at the end tells us which variable we're integrating with respect to (in this case, x).
When we integrate x^n (x raised to a power), we use this rule:
∫ x^n dx = (x^(n+1))/(n+1) + c
where n ≠ -1 (we can't use this rule when n = -1)
Step-by-step process:
Why do we add c? When we differentiate, any constant becomes zero. So when we integrate, we don't know what constant was there originally - it could have been any number. We write "+ c" to represent this unknown constant.
Examples:
Example 1: Integrate x³
∫ x³ dx = x^(3+1)/(3+1) + c = x⁴/4 + c
Example 2: Integrate x⁵
∫ x⁵ dx = x^(5+1)/(5+1) + c = x⁶/6 + c
Example 3: Integrate x^(-2) (the same as 1/x²)
∫ x^(-2) dx = x^(-2+1)/(-2+1) + c = x^(-1)/(-1) + c = -1/x + c
Sometimes we need to integrate expressions like (2x + 3)^4 or (5x - 1)^(-2). These are in the form (ax + b)^n where:
The formula is:
∫ (ax + b)^n dx = (ax + b)^(n+1) / [a(n+1)] + c
Step-by-step process:
Examples:
Example 4: Integrate (2x + 3)⁴
∫ (2x + 3)⁴ dx = (2x + 3)^(4+1) / [2(4+1)] + c = (2x + 3)⁵/10 + c
Here: a = 2, b = 3, n = 4
Example 5: Integrate 1/(2x + 3)²
First, rewrite this as (2x + 3)^(-2)
∫ (2x + 3)^(-2) dx = (2x + 3)^(-2+1) / [2(-2+1)] + c = (2x + 3)^(-1) / [2(-1)] + c = (2x + 3)^(-1) / (-2) + c
Simplifying: = -1/[2(2x + 3)] + c
Example 6: Integrate √(3x - 1)
First, write the square root as a power: √(3x - 1) = (3x - 1)^(1/2)
∫ (3x - 1)^(1/2) dx = (3x - 1)^(1/2 + 1) / [3(1/2 + 1)] + c = (3x - 1)^(3/2) / [3(3/2)] + c = (3x - 1)^(3/2) / (9/2) + c
Simplifying: = 2(3x - 1)^(3/2) / 9 + c
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