5.4 Surface Area and Volume


2026 Syllabus Objectives

By the end of this topic, you should be able to:

  1. Carry out calculations and solve problems involving the surface area and volume of a: cuboid, prism, cylinder, sphere, pyramid, and cone.
  2. Know which formulas are given to you in the exam (and which are not), and be able to leave answers in terms of π when asked.

What Are We Measuring?

Before diving into each shape, it helps to understand two big ideas:

  • Volume — how much space a 3D shape takes up. Think of it as how much water you could fill it with. Volume is measured in cubic units: cm³, m³, mm³.
  • Surface area — the total area of all the outer faces (sides) of a 3D shape. Think of it as how much wrapping paper you would need to cover the outside completely. Surface area is measured in square units: cm², m², mm².

Key strategy for surface area: Never try to memorise one formula for the whole surface area of every shape. Instead, find the area of each individual face, then add them all together. This approach works for every shape.


A cuboid is a box shape — like a brick or a cereal box. It has 6 rectangular faces. A cube is a special cuboid where all sides are the same length.

Volume of a Cuboid

Formula (not given in exam — you must remember this):

V=l×w×hV = l \times w \times h

Where:

  • ll = length
  • ww = width
  • hh = height

For a cube with side length LL: V=L3V = L^3

Surface Area of a Cuboid

A cuboid has three pairs of identical rectangular faces:

  • Top and bottom: each has area l×wl \times w → total 2(l×w)2(l \times w)
  • Front and back: each has area l×hl \times h → total 2(l×h)2(l \times h)
  • Left and right sides: each has area w×hw \times h → total 2(w×h)2(w \times h)

Formula (not given in exam):

TSA=2(lw)+2(lh)+2(wh)\text{TSA} = 2(lw) + 2(lh) + 2(wh)

For a cube with side LL: each face is a square with area L2L^2, and there are 6 faces:

TSA=6L2\text{TSA} = 6L^2

⚠️ Open containers: If a shape is described as an open container (like a box without a lid), you leave out the top face. Simply don't include that face's area in your total.

Worked Example — Cuboid

A cuboid has length 6 cm, width 4 cm, and height 3 cm. Find its volume and total surface area.

Volume:

V=6×4×3=72 cm3V = 6 \times 4 \times 3 = 72 \text{ cm}^3

Surface area:

TSA=2(6×4)+2(6×3)+2(4×3)\text{TSA} = 2(6 \times 4) + 2(6 \times 3) + 2(4 \times 3)

=2(24)+2(18)+2(12)= 2(24) + 2(18) + 2(12)

=48+36+24=108 cm2= 48 + 36 + 24 = 108 \text{ cm}^2

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