1.8 Graphs of Inverse Functions


2026 📌 Syllabus Objectives

By the end of these notes, you will be able to:

  • Use sketch graphs to show the relationship between a function and its inverse
  • Understand that the graph of a function and the graph of its inverse are reflections of each other in the line y = x

1. What Is the Line y = x?

Before we look at inverse function graphs, you need to be comfortable with the line y = x.

  • This is a straight diagonal line that passes through the origin (0, 0)
  • Every point on this line has an equal x-coordinate and y-coordinate — for example: (1, 1), (2, 2), (3, 3), (−4, −4)
  • It goes diagonally at a 45° angle, slanting upward to the right
  • This line acts like a mirror in our topic — it is the mirror line for inverse function graphs

💡 Think of y = x as a diagonal mirror placed at 45° across your graph.


2. The Relationship Between a Function and Its Inverse — The Reflection Rule

This is the core idea of this entire subtopic, so read carefully.

When you draw the graph of a function f(x) and its inverse f⁻¹(x) on the same set of axes, the two graphs are mirror images (reflections) of each other in the line y = x.

  • The graph of f⁻¹(x) is obtained by reflecting the graph of f(x) in the line y = x
  • This works the other way too — reflecting f⁻¹(x) in the line y = x gives you back f(x)
  • This is true for all one-to-one functions and their inverses

Why Does This Happen?

When you find an inverse function, you are essentially swapping x and y. For example:

  • If the point (a, b) is on the graph of f, then the point (b, a) is on the graph of f⁻¹
  • Swapping the x and y coordinates is exactly what a reflection in the line y = x does geometrically

💡 So every point on f becomes a "flipped" point on f⁻¹. The x and y values switch places.

Example to See This Clearly

Consider f(x) = 2x − 1 for the domain −1 ≤ x ≤ 3.

  • The domain of f is: −1 ≤ x ≤ 3 (the x-values the function accepts)

  • The range of f is: −3 ≤ f(x) ≤ 5 (the y-values the function produces)

    • When x = −1: f(−1) = 2(−1) − 1 = −3 → point (−1, −3)
    • When x = 3: f(3) = 2(3) − 1 = 5 → point (3, 5)

The inverse function is: f⁻¹(x) = (x + 1) ÷ 2

  • The domain of f⁻¹ is: −3 ≤ x ≤ 5 (the range of f becomes the domain of f⁻¹)

  • The range of f⁻¹ is: −1 ≤ f⁻¹(x) ≤ 3 (the domain of f becomes the range of f⁻¹)

    • When x = −3: f⁻¹(−3) = (−3 + 1) ÷ 2 = −1 → point (−3, −1)
    • When x = 5: f⁻¹(5) = (5 + 1) ÷ 2 = 3 → point (5, 3)

Now notice something important:

Point on fCorresponding point on f⁻¹
(−1, −3)(−3, −1)
(3, 5)(5, 3)

The coordinates are swapped — the x and y values switch. This is exactly what a reflection in y = x does.

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