12.4 AP and GP Formulas


2026 Syllabus Objectives

By the end of these notes, you should be able to:

  • Use the formula for the nth term of an arithmetic progression (AP) to solve problems
  • Use the formula for the sum of the first n terms of an AP to solve problems
  • Use the formula for the nth term of a geometric progression (GP) to solve problems
  • Use the formula for the sum of the first n terms of a GP to solve problems
  • Apply all of the above formulas to problems set in real-life contexts

Part 1: Arithmetic Progressions (AP)

What is an Arithmetic Progression?

A sequence is simply a list of numbers written in a specific order, following a rule.

An arithmetic progression (AP) is a special type of sequence where you always add the same number to get from one term to the next.

That fixed number you add each time is called the common difference, written as d.

Example: The sequence 5, 8, 11, 14, 17, ... is an AP.

  • From 5 to 8: add 3
  • From 8 to 11: add 3
  • From 11 to 14: add 3

So the common difference is d = 3.

💡 The common difference can be negative (sequence goes down) or even a decimal.


The Key Variables for an AP

SymbolWhat it means
aThe first term of the sequence
dThe common difference
nThe position of the term you want (1st, 2nd, 3rd, ...)
lThe last term of the sequence
SₙThe sum of the first n terms

The Terms of an AP — Spotting the Pattern

If you write out the first few terms, each term is built from the first term a plus multiples of d:

TermValue
1st terma
2nd terma + d
3rd terma + 2d
4th terma + 3d
5th terma + 4d

Notice: the nth term has (n − 1) lots of d added to a.


Formula 1: The nth Term of an AP

Tn=a+(n1)d\boxed{T_n = a + (n-1)d}

  • Tₙ = the value of the nth term
  • a = first term
  • n = position of the term
  • d = common difference

This formula lets you find any term in the sequence without listing every term before it.


Worked Example 1 — Finding the number of terms

Question: How many terms are in the AP: −17, −14, −11, −8, ..., 58?

Step 1: Identify the values.

  • a = −17 (first term)
  • d = −14 − (−17) = 3 (common difference)
  • Last term = 58

Step 2: Set the nth term formula equal to 58.

58=17+(n1)(3)58 = -17 + (n-1)(3)

Step 3: Solve for n. 58+17=3(n1)58 + 17 = 3(n-1) 75=3(n1)75 = 3(n-1) n1=25n - 1 = 25 n=26n = 26

Answer: There are 26 terms in this AP.

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