7.4 Linear Law Transformations


2026 📋 Syllabus Objectives

By the end of these notes, you will be able to:

  • Transform a non-linear equation (a curved relationship) into straight-line form Y=mX+cY = mX + c
  • Identify the correct variables to use for YY and XX after transformation
  • Determine unknown constants (like aa, bb, kk, nn) by reading the gradient and intercept from a transformed straight-line graph
  • Convert back from a straight-line graph to the original non-linear equation
  • Apply these skills to equations involving powers, exponentials, and logarithms

Part 1 — Why Do We Transform Equations?

In real life and in experiments, many relationships between two variables are not linear — meaning if you plot them on a graph, you get a curve, not a straight line.

Curves are much harder to work with than straight lines. It is difficult to read precise values from a curve or to find the equation of a curve from a graph.

The clever solution is this: change what you plot on each axis so that the curve becomes a straight line. This process is called linearisation or applying the linear law.

Once you have a straight line, you can:

  • Find the gradient mm (the slope of the line)
  • Find the YY-intercept cc (where the line crosses the vertical axis)
  • Use these two values to work out the unknown constants in the original equation

Part 2 — The Key Idea: The Standard Linear Form

Every straight line can be written as:

Y=mX+cY = mX + c

where:

  • YY is what you plot on the vertical axis (it may be a function of yy, not just yy itself)
  • XX is what you plot on the horizontal axis (it may be a function of xx, not just xx itself)
  • mm is the gradient — how steeply the line rises or falls
  • cc is the YY-intercept — the value of YY when X=0X = 0

Your job is always to rearrange the given non-linear equation until it looks exactly like Y=mX+cY = mX + c, then match up the pieces.


Part 3 — Transforming Non-Linear Equations TO Straight-Line Form

3.1 Equations of the Form y=Axny = Ax^n (Power Relationships)

This type of equation involves xx raised to a power nn. To linearise it, take logarithms (base 10, written lg\lg) of both sides.

Step-by-step:

y=Axny = Ax^n

Take lg\lg of both sides:

lgy=lg(Axn)\lg y = \lg(Ax^n)

Use log rules: lg(AB)=lgA+lgB\lg(AB) = \lg A + \lg B and lgxn=nlgx\lg x^n = n\lg x:

lgy=lgA+nlgx\lg y = \lg A + n\lg x

Rearrange to match Y=mX+cY = mX + c:

lgy=nlgx+lgA\lg y = n\lg x + \lg A

Now compare:

Part of Y=mX+cY = mX + cWhat it equals
YYlgy\lg y
XXlgx\lg x
mm (gradient)nn
cc (YY-intercept)lgA\lg A

So you plot lgy\lg y on the vertical axis against lgx\lg x on the horizontal axis. You get a straight line with gradient nn and YY-intercept lgA\lg A.

Finding the constants:

  • Read the gradient → that gives you nn directly
  • Read the intercept c=lgAc = \lg A → solve A=10cA = 10^c

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