14.12 Integrating Standard Functions


2026 Syllabus Objectives

By the end of this topic, you should be able to:

  • Integrate functions of the form (ax + b)ⁿ for any rational value of n (including n = −1)
  • Integrate sin(ax + b)
  • Integrate cos(ax + b)
  • Integrate sec²(ax + b)
  • Integrate e^(ax + b)
  • Always include an arbitrary constant (written as + c) in answers to indefinite integrals
  • Know that all angles in trigonometric integrals are measured in radians

What is Integration?

Integration is the reverse process of differentiation. When you differentiate a function, you find its gradient. When you integrate, you work backwards — you find the original function from the gradient.

Because integration is the reverse of differentiation, the best way to understand each integration rule is to start from what you already know about differentiation and work backwards.

Indefinite integral — an integral without upper and lower limits. The answer always includes + c, called the arbitrary constant, because when you differentiate any constant, it disappears. Since we don't know what constant was there originally, we always add + c to show that it could be anything.


Section 1: Integrating (ax + b)ⁿ

The Rule

When you have a linear expression (something of the form ax + b) raised to a power n, use this formula:

(ax+b)ndx=1a(n+1)(ax+b)n+1+c\int (ax + b)^n \, dx = \frac{1}{a(n+1)}(ax + b)^{n+1} + c

Conditions:

  • n1n \neq -1 (we handle n = −1 separately — see below)
  • a0a \neq 0

How to read this formula: Raise the power by 1, then divide by the new power AND divide by a (the coefficient of x). Always add + c.

Where does this rule come from?

Think about differentiation. You know that:

ddx[1a(n+1)(ax+b)n+1]=1a(n+1)×a(n+1)(ax+b)n=(ax+b)n\frac{d}{dx}\left[\frac{1}{a(n+1)}(ax+b)^{n+1}\right] = \frac{1}{a(n+1)} \times a(n+1)(ax+b)^n = (ax+b)^n

So working backwards, the integral of (ax+b)n(ax+b)^n must be 1a(n+1)(ax+b)n+1+c\dfrac{1}{a(n+1)}(ax+b)^{n+1} + c.


Step-by-Step Example 1: Positive integer power

Find (3x8)5dx\int (3x - 8)^5 \, dx

Here, a=3a = 3, b=8b = -8, n=5n = 5.

Step 1: Raise the power by 1: 5+1=65 + 1 = 6

Step 2: Write (3x8)6(3x - 8)^6

Step 3: Divide by the new power (6) and by aa (3): divide by 3×6=183 \times 6 = 18

Answer:

(3x8)5dx=118(3x8)6+c\int (3x - 8)^5 \, dx = \frac{1}{18}(3x - 8)^6 + c

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