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By the end of these notes, you should be able to:
Before solving equations, you need to know all six trigonometric functions and how they relate to each other. Think of them as a family — three "main" functions and three "reciprocal" (flipped) functions.
The three main functions:
| Function | Definition | What it means |
|---|---|---|
| sin θ | opposite ÷ hypotenuse | The ratio of the side opposite the angle to the longest side |
| cos θ | adjacent ÷ hypotenuse | The ratio of the side next to the angle to the longest side |
| tan θ | opposite ÷ adjacent | The ratio of the opposite side to the adjacent side |
The three reciprocal functions (each is 1 divided by a main function):
| Function | Definition | Plain English |
|---|---|---|
| cosec θ | 1 ÷ sin θ | "Cosecant" — the flip of sine |
| sec θ | 1 ÷ cos θ | "Secant" — the flip of cosine |
| cot θ | 1 ÷ tan θ = cos θ ÷ sin θ | "Cotangent" — the flip of tangent |
💡 Memory tip: The reciprocal of a function is simply 1 divided by it. So cosec is just 1/sin, sec is just 1/cos, and cot is just 1/tan.
These identities are tools. When an equation looks impossible to solve directly, you swap one expression for another using these identities, making the equation simpler.
tanθ=cosθsinθ
This tells you that tan can always be written as sin divided by cos. Very useful when an equation mixes sin, cos, and tan.
These three identities all come from the same source — the Pythagorean theorem (a² + b² = c²) applied to a unit circle.
Identity 1 (The most important one): sin2θ+cos2θ=1
From this, you can rearrange to get:
Identity 2 (Involves sec and tan): 1+tan2θ=sec2θ
This comes from dividing Identity 1 through by cos2θ.
Rearranged: tan2θ=sec2θ−1
Identity 3 (Involves cosec and cot):
cot2θ+1=cosec2 θThis comes from dividing Identity 1 through by sin2θ.
Rearranged: cot2θ=cosec2 θ−1
💡 Why these matter: Many exam questions give you an equation with sec, tan, cosec, or cot mixed together. You convert everything to sin and cos using the identities above, then solve.
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