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By the end of these notes, you should be able to:
The gradient of a curve at any point tells you how steep the curve is at that exact point. Unlike a straight line (which has the same steepness everywhere), a curve's steepness changes from point to point.
To find the gradient of a curve at a specific point, you:
💡 Remember: dxdy is the derivative — it gives you a formula for the gradient at any x-value.
A tangent is a straight line that just touches a curve at one point without crossing through it. At the point of contact, the tangent has exactly the same gradient (steepness) as the curve.
Think of it like this: if you zoomed in very closely on the curve at a point, it would look like a straight line — that straight line is the tangent.
To find the equation of a tangent at a point (x1,y1):
Step 1: Differentiate y to get dxdy.
Step 2: Substitute x=x1 into dxdy to find the gradient m.
Step 3: If you are only given the x-value, substitute it into the original equation y=... to find y1.
Step 4: Use the straight-line formula:
y−y1=m(x−x1)
where (x1,y1) is the point on the curve and m is the gradient found in Step 2.
A normal is a straight line that is perpendicular (at a right angle, 90°) to the tangent at the same point on the curve.
If two lines are perpendicular to each other, their gradients multiply to give −1. This means:
mtangent×mnormal=−1So, if the gradient of the tangent is m, then:
mnormal=−m1In plain English: flip the tangent gradient and change its sign to get the normal gradient.
⚠️ This only works when m=0. If the tangent is horizontal (gradient = 0), the normal is a vertical line.
Step 1: Find the gradient of the tangent, m, at the point (same as for the tangent — differentiate and substitute the x-value).
Step 2: Calculate the gradient of the normal: −m1.
Step 3: Use the same straight-line formula, but with the normal's gradient:
y−y1=−m1(x−x1)
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