5.1 Solving Simultaneous Equations


2026 Syllabus Objectives

By the end of these notes, you will be able to:

  • Solve simultaneous equations in two unknowns using the elimination method
  • Solve simultaneous equations in two unknowns using the substitution method
  • Apply these methods to pairs of equations where one or both equations are non-linear (for example, equations involving x², xy, or fractions)

What Are Simultaneous Equations?

Simultaneous equations are a pair (or group) of equations that share the same unknown variables — usually x and y. The word "simultaneous" means "at the same time," so you are looking for values of x and y that satisfy both equations at the same time.

For example:

  • Equation 1: x + y = 5
  • Equation 2: x − y = 1

The solution is the pair of values (x, y) that makes both statements true.

There are two main methods to solve simultaneous equations:

  1. The Elimination Method
  2. The Substitution Method

Method 1: The Elimination Method

What it means: You manipulate the two equations so that one of the variables cancels out (is "eliminated"), leaving you with a single equation in just one unknown.

When to use it: Elimination works best when both equations are linear (no x², xy, or other powers — just plain x and y terms).


Step-by-Step Guide to Elimination

Step 1: Make the coefficient (the number in front) of one variable the same in both equations. You do this by multiplying one or both equations by a suitable number.

Step 2: Add or subtract the two equations to eliminate that variable.

Step 3: Solve the resulting single-variable equation.

Step 4: Substitute the value you found back into one of the original equations to find the second variable.

Step 5: Check your answer in both original equations.


Worked Example 1 — Elimination with Equal Coefficients

Solve:

  • 4x + 3y = 1 ← Equation (1)
  • 2x − 3y = 14 ← Equation (2)

Step 1: Notice that the y terms are already +3y and −3y. The coefficients are the same (both 3). ✓

Step 2: Add the two equations together:

(4x + 3y) + (2x − 3y) = 1 + 14

6x = 15

Step 3: Divide both sides by 6:

x = 15 ÷ 6 = 2.5

Step 4: Substitute x = 2.5 into Equation (1):

4(2.5) + 3y = 1 10 + 3y = 1 3y = 1 − 10 = −9 y = −9 ÷ 3 = −3

Solution: x = 2.5, y = −3

Check in Equation (2): 2(2.5) − 3(−3) = 5 + 9 = 14 ✓

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