4.1 Solving Modulus Equations


2026 📋 Syllabus Objectives

By the end of these notes, you will be able to:

  • Solve equations of the type |ax + b| = c (where c ≥ 0)
  • Solve equations of the type |ax + b| = cx + d
  • Solve equations of the type |ax + b| = |cx + d|
  • Solve equations of the type |ax² + bx + c| = d
  • Use both algebraic methods and graphical methods to solve all of the above

What is a Modulus (Absolute Value)?

Before solving any equations, you need to understand what the modulus symbol means.

The modulus of a number is its distance from zero on a number line. Distance is always positive, so the modulus of any number is always zero or positive — never negative.

The modulus is written using two vertical bars: |x|

Examples:

  • |5| = 5 (5 is already positive, so it stays as 5)
  • |−5| = 5 (−5 is negative, so we make it positive)
  • |0| = 0

The formal rule:

x=xif x0|x| = x \quad \text{if } x \geq 0 x=xif x<0|x| = -x \quad \text{if } x < 0

This means: if the expression inside the bars is positive or zero, keep it as it is. If it is negative, multiply it by −1 to make it positive.

Example:

  • |3x − 1| = 3x − 1 when 3x − 1 ≥ 0 (i.e. when x ≥ 1/3)
  • |3x − 1| = −(3x − 1) when 3x − 1 < 0 (i.e. when x < 1/3)

The Graph of y = |ax + b|

The graph of a modulus function looks like a V-shape.

  • The graph of y = |x| is a V with its vertex (tip/bottom point) at the origin (0, 0)
  • The graph of y = |ax + b| has its vertex where ax + b = 0, i.e. at x = −b/a
  • The arms of the V always go upward — the y-values are never negative

Example: y = |x − 5|

  • Vertex is where x − 5 = 0, so at x = 5 → vertex is at (5, 0)
  • When x > 5: y = x − 5 (a straight line going up to the right)
  • When x < 5: y = −(x − 5) = −x + 5 (a straight line going up to the left)

Type 1: Solving |ax + b| = c

This is the simplest type. Here, c is a constant (a fixed number) and c ≥ 0.

The key idea: If |something| = c, then that "something" equals +c or −c.

ax+b=c    ax+b=corax+b=c|ax + b| = c \implies ax + b = c \quad \text{or} \quad ax + b = -c

⚠️ Important: If c < 0, there is no solution, because a modulus can never be negative.

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