6.3 Solving Exponential Equations


2026 Syllabus Objectives

By the end of these notes, you will be able to:

  • Solve equations of the form ax=ba^x = b, where the unknown is in the exponent (power).

What is an Exponential Equation?

An exponential equation is an equation where the unknown (the letter you are solving for, usually xx) appears as a power (exponent).

For example: 2x=83x=205x=1002^x = 8 \qquad 3^x = 20 \qquad 5^x = 100

In the first example, 2x=82^x = 8, you might already know the answer is x=3x = 3 because 23=82^3 = 8. But what about 3x=203^x = 20? You cannot easily spot the answer — this is where logarithms come in.


The Key Tool: Logarithms

A logarithm is the inverse (opposite) of a power. In plain English:

If ax=ba^x = b, then logab=x\log_a b = x.

This means: "What power do I raise aa to, in order to get bb?"

However, in exam questions, you will almost always use common logarithms (written as log\log, base 10) or natural logarithms (written as ln\ln, base ee). Both work — just be consistent.

The most important log rule you need here is:

The Power Rule: log(ax)=xloga\log(a^x) = x \log a

This rule lets you bring the power down in front of the log, turning a difficult exponential equation into a straightforward linear equation.


The Method: Solving ax=ba^x = b

Follow these steps every time:

Step 1: Take log\log (or ln\ln) of both sides of the equation.

Step 2: Use the Power Rule to bring xx down in front of the log.

Step 3: Divide both sides by the log term to isolate xx.

Step 4: Use a calculator to find the decimal answer (unless an exact answer is asked for).


Worked Example 1 — Simple Case

Solve 3x=203^x = 20.

Step 1: Take log\log of both sides. log(3x)=log20\log(3^x) = \log 20

Step 2: Apply the Power Rule — bring the power xx to the front. xlog3=log20x \log 3 = \log 20

Step 3: Divide both sides by log3\log 3. x=log20log3x = \frac{\log 20}{\log 3}

Step 4: Use a calculator.

x=1.3010...0.4771...2.727(to 3 s.f.)x = \frac{1.3010...}{0.4771...} \approx 2.727 \quad \text{(to 3 s.f.)}

Answer: x2.73x \approx 2.73


Worked Example 2 — Coefficient in Front of xx

Solve 52x=805^{2x} = 80.

Step 1: Take log\log of both sides. log(52x)=log80\log(5^{2x}) = \log 80

Step 2: Apply the Power Rule. 2xlog5=log802x \log 5 = \log 80

Step 3: Divide both sides by log5\log 5. 2x=log80log52x = \frac{\log 80}{\log 5}

Step 4: Divide by 2. x=log802log5x = \frac{\log 80}{2 \log 5}

Step 5: Use a calculator. x=1.9031...2×0.6990...=1.9031...1.3979...1.361x = \frac{1.9031...}{2 \times 0.6990...} = \frac{1.9031...}{1.3979...} \approx 1.361

Answer: x1.36x \approx 1.36 (to 3 s.f.)

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