3.1 Remainder and Factor Theorems


2026 📋 Syllabus Objectives

By the end of these notes, you will be able to:

  • Know and use the Remainder Theorem to find the remainder when a polynomial is divided by a linear expression
  • Know and use the Factor Theorem to determine whether a linear expression is a factor of a polynomial, and to find unknown constants

What is a Polynomial?

A polynomial is an expression made up of terms with non-negative whole-number powers of xx. For example:

P(x)=2x35x2+3x7P(x) = 2x^3 - 5x^2 + 3x - 7

This is called a cubic polynomial because the highest power is 3. We write P(x)P(x) (read as "P of x") to show it's a function — meaning we can substitute any value of xx into it.

Substituting a value means replacing xx with a number. For example, if P(x)=x2+1P(x) = x^2 + 1, then P(3)=32+1=10P(3) = 3^2 + 1 = 10.


Part 1 — The Remainder Theorem

The Big Idea

Normally, when you divide one number by another, you might get a remainder. For example, 17÷5=317 \div 5 = 3 remainder 22.

The same thing happens with polynomials. When you divide a polynomial P(x)P(x) by a linear factor (an expression like xcx - c), you usually get a quotient (the main result) and a remainder (what's left over).

The Remainder Theorem gives you a shortcut to find that remainder — without doing any long division at all.


The Remainder Theorem — Statement

If a polynomial P(x)P(x) is divided by (xc)(x - c), then the remainder is P(c)P(c).

In other words: to find the remainder, just substitute x=cx = c into the polynomial.

Where does this come from?

When P(x)P(x) is divided by (xc)(x - c), we can write:

P(x)=(xc)Q(x)+RP(x) = (x - c) \cdot Q(x) + R

Here, Q(x)Q(x) is the quotient and RR is the remainder (a number, not an expression).

Now substitute x=cx = c:

P(c)=(cc)Q(c)+R=0Q(c)+R=RP(c) = (c - c) \cdot Q(c) + R = 0 \cdot Q(c) + R = R

So P(c)=RP(c) = R. The remainder is simply the value of the polynomial at x=cx = c.


Worked Example 1 — Basic Remainder

Find the remainder when 7x3+6x240x+177x^3 + 6x^2 - 40x + 17 is divided by (x+3)(x + 3).

Step 1: Write the divisor in the form (xc)(x - c).

(x+3)=(x(3))(x + 3) = (x - (-3)), so c=3c = -3.

Step 2: Substitute x=3x = -3 into the polynomial.

P(3)=7(3)3+6(3)240(3)+17P(-3) = 7(-3)^3 + 6(-3)^2 - 40(-3) + 17

=7(27)+6(9)+120+17= 7(-27) + 6(9) + 120 + 17

=189+54+120+17= -189 + 54 + 120 + 17

=2= \mathbf{2}

The remainder is 2.

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