8.1 Circle Equations


2026 Syllabus Objectives

By the end of these notes, you will be able to:

  • Know and use the equation of a circle with radius r and centre (a, b)
  • Identify the centre and radius of a circle written in completed square form: (xa)2+(yb)2=r2(x - a)^2 + (y - b)^2 = r^2
  • Identify the centre and radius of a circle written in general form: x2+y2+2gx+2fy+c=0x^2 + y^2 + 2gx + 2fy + c = 0
  • Convert between the two forms using a technique called completing the square

What is a Circle?

A circle is the set of all points in a flat plane that are the exact same distance from one fixed point. That fixed point is called the centre, and that fixed distance is called the radius.

Think of it like this: if you tie a piece of string to a pin on a piece of paper, hold the string tight, and trace all the way around — every point your pencil touches is the same distance from the pin. That traced path is a circle.


Deriving the Equation of a Circle

To write an equation that describes a circle, we use Pythagoras' theorem — the rule that says in a right-angled triangle, the square of the longest side equals the sum of the squares of the other two sides.

Here is how we do it:

  • Let the centre of the circle be the point C(a,b)C(a, b)
  • Let any point on the circle be P(x,y)P(x, y)
  • The distance from CC to PP is always equal to the radius rr

If you draw a right-angled triangle between CC and PP:

  • The horizontal side has length xax - a
  • The vertical side has length yby - b
  • The hypotenuse (the slanted side from centre to point) has length rr

Applying Pythagoras' theorem:

(xa)2+(yb)2=r2\boxed{(x - a)^2 + (y - b)^2 = r^2}

This is the equation of a circle with centre (a,b)(a, b) and radius rr.


Form 1 — Completed Square Form

(xa)2+(yb)2=r2\mathbf{(x - a)^2 + (y - b)^2 = r^2}

This is the most useful form because the centre and radius can be read off directly.

What you seeWhat it means
(xa)2(x - a)^2The xx-coordinate of the centre is +a+a
(yb)2(y - b)^2The yy-coordinate of the centre is +b+b
r2r^2 on the rightSquare root this to get the radius

⚠️ Be careful with signs! The formula uses minus signs inside the brackets. If you see (x+4)2(x + 4)^2, rewrite it as (x(4))2(x - (-4))^2, so the xx-coordinate of the centre is 4-4, not +4+4.

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